Adobe Exam AD0-E213 Topic 3 Question 41 Discussion

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Jeannine

3 months ago

Wait, is the function called 'V' or is that just a variable name in the question? I'm so confused right now...

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Elly

3 months ago

I'm going to have to go with B. Seems like the most straightforward way to get that particular error message.

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Salome

3 months ago

Option A sounds plausible, but I'm not sure if that's the only way this error can occur. Maybe it's a trick question!

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Dorcas

2 months ago

C) When the type of the value returned by function V does not match its declared type.

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Louvenia

2 months ago

User 3: Maybe it's a combination of both scenarios that can cause that error.

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Viola

2 months ago

B) When function V is called after it is defined.

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Aretha

2 months ago

A) When function V shares its name with a variable define earlier.

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Christoper

2 months ago

User 2: I think it could also happen if function V is called before it is defined.

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Lindsey

2 months ago

User 1: Option A is a common reason for that error.

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Alpha

3 months ago

Hmm, I'm going with C. If the function is expecting a specific data type and it gets something else, that could definitely cause a TypeError.

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Margurite

2 months ago

I'm not sure, but I think it could also be A. Sharing a name with a variable might cause confusion.

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Elsa

2 months ago

I agree with you, it's definitely B. Calling a function before it's defined can lead to that error.

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Yun

3 months ago

I think it's B. If you call a function before it's defined, that could cause a TypeError.

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Herminia

3 months ago

I think it's option B. Calling a function before it's defined seems like a common way to trigger that error.

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Annmarie

2 months ago

I think it's option C. The type of the value returned by the function not matching its declared type could also trigger the error.

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Annmarie

2 months ago

I agree, calling a function before it's defined can definitely cause that error.

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Verlene

2 months ago

I think it's actually option A, when a function shares its name with a variable defined earlier.

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Jody

2 months ago

I agree, calling a function before it's defined can definitely cause that error.

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Willis

3 months ago

I think it's option A, when a function shares its name with a variable defined earlier.

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Willis

3 months ago

I agree, calling a function before it's defined can definitely cause that error.

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