CIW Exam 1D0-735 Topic 4 Question 69 Discussion

Actual exam question for CIW's 1D0-735 exam

Question #: 69
Topic #: 4

[All 1D0-735 Questions]

Consider the following code:

What change should be made to ensure that it correctly displays the value of name in all uppercase letters?

ALine 2 should be changed to name = name . toUpperCase () ;

BLine 2 should be changed to name .prototype . toUpperCase () ;

CLine 3 should be changed to document. write (NAME) :

DLine 1 should be changed to var name = new sting('Jaccb');

Show Suggested Answer

Suggested Answer: B

by Dante at Sep 13, 2024, 04:00 AM

Limited Time Offer

25%

Off

Get Premium 1D0-735 Questions as Interactive Web-Based Practice Test or PDF

Contribute your Thoughts:

Submit Cancel

Annelle

1 months ago

I'm cracking up at the typo in Option D. 'sting' instead of 'string'? Somebody needs to proofread these exam questions!

upvoted 0 times

William

14 days ago

User 3: Definitely, that typo could confuse someone during the exam.

upvoted 0 times

...

Kati

26 days ago

User 2: I know right, they really need to proofread these questions better.

upvoted 0 times

...

Monroe

1 months ago

User 1: Option D is hilarious, 'sting' instead of 'string'!

upvoted 0 times

...

Alana

2 months ago

Option C looks promising, but I'm not sure if document.write() is the best way to display the value. Might be better to use innerHTML or textContent.

upvoted 0 times

Rashad

19 days ago

Option C looks promising, but I'm not sure if document.write() is the best way to display the value. Might be better to use innerHTML or textContent.

upvoted 0 times

...

Marlon

1 months ago

B) Line 2 should be changed to name .prototype . toUpperCase () ;

upvoted 0 times

...

Lynette

1 months ago

A) Line 2 should be changed to name = name . toUpperCase () ;

upvoted 0 times

...

Meghan

2 months ago

Haha, Option B is clearly a joke. Why would we need to call toUpperCase() on the prototype? That's just silly.

upvoted 0 times

Selma

24 days ago

Kimberlie: I think so too, calling toUpperCase() directly on the string variable makes more sense.

upvoted 0 times

...

Yesenia

26 days ago

User 3: Option A seems like the correct answer to me.

upvoted 0 times

...

Kimberlie

1 months ago

User 2: Yeah, it's definitely not the right choice.

upvoted 0 times

...

Tasia

1 months ago

User 1: I agree, Option B doesn't make any sense.

upvoted 0 times

...

Alecia

2 months ago

I think Option D is the way to go. We need to create a new String object to ensure the name is properly defined.

upvoted 0 times

Sena

26 days ago

User 2: Line 1 should be changed to var name = new String(\'Jaccb\').

upvoted 0 times

...

Micah

1 months ago

User 1: I think Option D is the way to go. We need to create a new String object to ensure the name is properly defined.

upvoted 0 times

...

Tanja

2 months ago

Option A is the correct answer. We need to call the toUpperCase() method on the name variable to convert it to uppercase.

upvoted 0 times

...

Daisy

2 months ago

I'm not sure, but I think the answer might be C.

upvoted 0 times

...

Lyndia

3 months ago

I disagree, I believe the correct answer is B.

upvoted 0 times

...

Marsha

3 months ago

I think the answer is A.

upvoted 0 times

...