Huawei Exam H12-891_V1.0 Topic 1 Question 54 Discussion

Actual exam question for Huawei's H12-891_V1.0 exam

Question #: 54
Topic #: 1

[All H12-891_V1.0 Questions]

What is the correct description of the scene shown in the following figure?

AR1 simultaneously exists level-1 and Level-2 LSDB

BR1 can ping the interface address of R2 loopback 0

CR1 has a route to R2 loopback 010022/32

DThere is no neighbor relationship between R1 and R2

Show Suggested Answer

Suggested Answer: A, C

by Aide at Sep 19, 2024, 04:04 PM

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Jacquline

2 months ago

Option A? Really? I thought this was a networking exam, not a shape-shifting quiz!

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Jeniffer

2 months ago

This question is a bit tricky. I'd go with C, but I'm not 100% sure.

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Zoila

25 days ago

I'm not sure about that, I would go with A) R1 simultaneously exists level-1 and Level-2 LSDB.

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Maile

28 days ago

I agree with you, I also think it's B) R1 can ping the interface address of R2 loopback 0.

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Ceola

1 months ago

I think the correct answer is B) R1 can ping the interface address of R2 loopback 0.

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Bea

2 months ago

D seems more likely. If there's no neighbor relationship, then R1 wouldn't be able to see R2's loopback address.

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Selma

2 months ago

I think B is the right answer. If R1 can ping R2's loopback, then they must have a valid adjacency.

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Amie

25 days ago

C) R1 has a route to R2 loopback 010022/32

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Evangelina

26 days ago

B) R1 can ping the interface address of R2 loopback 0

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Claudia

1 months ago

A) R1 simultaneously exists level-1 and Level-2 LSDB

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Amie

2 months ago

I'm not sure, but I think it might be A) R1 simultaneously exists level-1 and Level-2 LSDB.

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Lashonda

3 months ago

I agree with Titus. R1 being able to ping R2's loopback 0 address makes sense.

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Arthur

3 months ago

Option C looks correct to me. R1 should have a route to the loopback interface of R2 if they're connected.

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Bette

2 months ago

Yeah, that's true. If they're connected, R1 should definitely have a route to R2's loopback interface.

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Christiane

3 months ago

I think option C is correct too. It makes sense that R1 would have a route to R2's loopback interface.

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Titus

3 months ago

I think the correct description is B) R1 can ping the interface address of R2 loopback 0.

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