NFPA Exam CWBSP Topic 2 Question 3 Discussion

Actual exam question for NFPA's CWBSP exam

Question #: 3
Topic #: 2

[All CWBSP Questions]

A 4.2 K-factor sprinkler must deliver 17 gpm (692 mm/min). What pressure is required?

A4.52 psi (0.31 bar)

B9.22 psi (0.63 bar)

C16.38 psi (1.13 bar)

D36.86 psi (2.54 bar)

Show Suggested Answer

Suggested Answer: B

To deliver 17 gpm with a 4.2 K-factor sprinkler, approximately 9.22 psi pressure is required. This is calculated using the sprinkler's K-factor formula, which relates flow rate, pressure, and the K-factor.

by Ruthann at Nov 13, 2024, 08:05 PM

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Cecily

5 days ago

Hmm, I'm gonna go with D) 36.86 psi (2.54 bar). Bigger is better, right? Just like my ego after acing this exam.

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Justine

17 days ago

I'm not sure, but I think I'll go with D) 36.86 psi (2.54 bar)

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Brande

19 days ago

I agree with Paris, because the formula for pressure is flow rate divided by K-factor

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Golda

20 days ago

I think B) 9.22 psi (0.63 bar) is the right answer. Gotta love these sprinkler questions, they really get the blood flowing!

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Yuriko

21 days ago

C) 16.38 psi (1.13 bar) seems like the correct answer. The K-factor and flow rate are given, so we can plug those into the formula to solve for the pressure.

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Lavonne

7 days ago

So, for this problem, it would be 4.2 multiplied by the square root of 17.

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Ilene

12 days ago

I think the formula to calculate pressure is K-factor multiplied by the square root of the flow rate.

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Paris

26 days ago

I think the answer is C) 16.38 psi (1.13 bar)

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