OMG Exam OMG-OCSMP-MBI300 Topic 1 Question 47 Discussion

Actual exam question for OMG's OMG-OCSMP-MBI300 exam

Question #: 47
Topic #: 1

[All OMG-OCSMP-MBI300 Questions]

Choose the correct answer.

Given the following state machine, and assuming that it starts from initialization:

Which option is the shortest sequence of events that will cause the machine to be in state E?

Ae1, e2, e6, e7

Be1, e2, e6, e7, e1

Ce1, e2, e6, e7, e2

De1, e2, e3, e6, e7, e2

Ee1, e2, e3, e3, e6, e7, e1, e2

Show Suggested Answer

Suggested Answer: A

by Nenita at Jun 01, 2024, 07:35 AM

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Lauran

4 days ago

D and E seem way too long, I'm not trying to take the scenic route here. A is the way to go, get me to state E with the fewest steps!

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Hannah

20 days ago

Hmm, option B and C both involve repeating events, which seems unnecessary. I'm going to go with A, keep it simple.

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Justine

6 days ago

I agree, repeating events in B and C seem unnecessary.

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Dylan

7 days ago

I think A is the best choice, it's the shortest sequence.

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Gladys

22 days ago

Alright, let's see... The question is asking for the shortest sequence of events to reach state E. I think option A looks the most straightforward, no need to double back.

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Adelina

9 days ago

Option A) e1, e2, e6, e7 seems like the best choice.

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Jess

27 days ago

Hmm, I see your point. Let's analyze the state machine again to determine the shortest sequence of events.

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Annamae

29 days ago

I disagree, I believe the correct answer is D) e1, e2, e3, e6, e7, e2.

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Jess

1 months ago

I think the answer is A) e1, e2, e6, e7.

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