Oracle Exam 1Z0-497 Topic 3 Question 101 Discussion

Actual exam question for Oracle's 1Z0-497 exam

Question #: 101
Topic #: 3

[All 1Z0-497 Questions]

Examine the command below:

BEGIN DBMS_REDACT.ADD_POLICY(

object_schema => 'mavis',

object_name => 'cust_info',

column_name => 'emp_id',

policy_name => 'redact_cust_ids',

function_type => DBMS_REDACT.REGEXP,

expression => '1=1',

regexp_pattern => '(\d\d\d)(\d\d)(\d\d\d\d)',

regexp_replace_string => 'XXXXX\3',

regexp_position => 1,

regexp_occurrence => 0,

regexp_match_parameter => 'i',

policy_description => 'Redacts customer IDs',

column_description => 'emp_id contains employee ID numbers');

END;

What do the regexp_pattern and regexp_replace_string parameters accomplish?

AThey find a pattern of nine digits; break the digits into three groups that contain the first three, the next two and then the last four digits; and replace all digits with XXXXX concatenated with the last four digits.

BThey find a pattern of six digits; break the digits into two groups that contain the first five, and then the last digit; and replace all digits with XXXXX concatenated with the last digit.

CThey find a pattern of nine digits and display the digits as XXXXX XX XXXX.

DThey find a pattern of nine digits and display the first five digits as XXXXX and the last four digits as 3333.

Show Suggested Answer

Suggested Answer: A

http://docs.oracle.com/database/121/ASOAG/redaction_features.htm#ASOAG925

by Van at Sep 07, 2024, 01:38 PM

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Vanesa

3 months ago

I see your point, Jordan. But I still think Option A is the most logical choice.

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Ailene

3 months ago

As a wise man once said, 'With great power comes great responsibility.' I hope the folks using this redaction policy are using it responsibly. A gets my vote.

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Jordan

3 months ago

I'm not sure. Option D also sounds plausible to me.

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3 months ago

The regular expression and replace string seem to work as expected. It finds a pattern of 9 digits, breaks it into groups, and replaces the first 5 digits with XXXXX and keeps the last 4 digits. I'd go with option A.

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Eileen

2 months ago

Yes, option A is the right choice. It breaks the 9 digits into groups and replaces all digits except the last four with XXXXX.

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Eileen

2 months ago

I agree, option A is correct. It breaks the 9 digits into groups and replaces all digits except the last four with XXXXX.

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Vanesa

3 months ago

I think the regexp_pattern and regexp_replace_string parameters break the digits into three groups and replace them with XXXXX.

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