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Oracle Exam 1Z0-533 Topic 3 Question 59 Discussion

Actual exam question for Oracle's 1Z0-533 exam
Question #: 59
Topic #: 3
[All 1Z0-533 Questions]

Given the following:

Measures (Dense): 40 stored members, 50 total members Time (Dense): 17 stored members, 17

total members Scenario (Dense): 2 stored members, 5 total members Market (Sparse): 100 stored

members, 100 total members Product(Sparse): 500 stored members, 550 total members

What is the block size in bytes?

Show Suggested Answer Hide Answer
Suggested Answer: C

Contribute your Thoughts:

Aleshia
5 months ago
Yes, I agree with that reasoning. The block size should be 40 * 17 * 2 * 8.
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Raul
5 months ago
That makes sense. So the answer would be Block size = 40 * 17 * 2 * 8.
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Shayne
5 months ago
I believe the correct formula should include multiplying by 8 to convert to bytes.
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Carlton
6 months ago
So, for the Measures dimension, the calculation would be 40 * 17 * 2.
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Aleshia
6 months ago
I agree. We need to consider both the stored and total members for each dimension.
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Raul
6 months ago
I think the block size should be calculated using the number of stored members and total members.
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Alison
6 months ago
I see your point, Mireya. Maybe we should revisit the formulas and calculations to ensure accuracy.
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Mireya
6 months ago
That makes sense, Vanna. The block size should take into account the total members for each dimension.
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Vanna
6 months ago
I disagree with Alison. I think the block size should be calculated differently, maybe Block size = 50 * 17 * 5.
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Alison
6 months ago
I believe the correct formula to calculate the block size is Block size = 40 * 17 * 2 * 8.
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Mireya
7 months ago
I think the block size should be calculated based on the measures and time stored members.
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