Oracle Exam 1Z0-809 Topic 9 Question 70 Discussion

Actual exam question for Oracle's 1Z0-809 exam

Question #: 70
Topic #: 9

[All 1Z0-809 Questions]

Given the code fragment:

Which modification enables the code to print Price 5 New Price 4?

AReplace line n2 with .map (n -> System.out.println (''New Price'' + n --1)) and remove line n3

BReplace line n2 with .mapToInt (n -> n -- 1);

CReplace line n1 with .forEach (e -> System.out.print (''Price'' + e))

DReplace line n3 with .forEach (n -> System.out.println (''New Price'' + n));

Show Suggested Answer

Suggested Answer: D

by Avery at Aug 28, 2024, 12:45 PM

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Cherelle

2 months ago

I'm going with option A. Replacing line n2 with .map (n -> System.out.println (''New Price'' + n --1)) and removing line n3 should do the trick.

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Tamera

1 months ago

I'm not sure, but I would go with option B.

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Silva

1 months ago

I disagree, I believe option D is the right choice.

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Merlyn

2 months ago

I think option A is the correct one.

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Steffanie

3 months ago

Haha, I bet the real answer is to just add a '+' to the 'New Price' string! Developers love their shortcuts.

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Devorah

2 months ago

Haha, I bet the real answer is to just add a '+' to the 'New Price' string! Developers love their shortcuts.

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Ayesha

2 months ago

Maybe it's B) Replace line n2 with .mapToInt (n -> n -- 1);

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Vince

2 months ago

No, I believe it's A) Replace line n2 with .map (n -> System.out.println ('New Price' + n --1)) and remove line n3

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Nichelle

2 months ago

I think the answer is D) Replace line n3 with .forEach (n -> System.out.println ('New Price' + n));

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Elouise

3 months ago

I see your point, Hubert. I think you're right. The answer is D.

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Hubert

3 months ago

But if you replace line n3 with .forEach (n -> System.out.println (''New Price'' + n)), it will print Price 5 New Price 4.

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Erick

3 months ago

Option D seems more straightforward to me. Replacing line n3 with .forEach (n -> System.out.println (''New Price'' + n)) will directly print the new price.

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Lorrie

3 months ago

I think option B is the correct answer. Replacing line n2 with .mapToInt (n -> n -- 1) will decrement each value by 1 and print the new price.

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Bernadine

3 months ago

Yes, I think so too. It makes sense to decrement each value by 1 to get the new price.

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Nakita

3 months ago

I agree with you, option B seems like the correct choice.

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Blondell

3 months ago

I disagree, I believe the answer is A.

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Hubert

4 months ago

I think the answer is D.

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