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Oracle Exam 1Z0-900 Topic 2 Question 81 Discussion

Actual exam question for Oracle's 1Z0-900 exam
Question #: 81
Topic #: 2
[All 1Z0-900 Questions]

Which code snippet indicates that the page you are designing is capable of handling errors?

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Suggested Answer: C

Contribute your Thoughts:

Glen
6 months ago
Option A is the way to go. I don't know about you, but I prefer my pages to handle errors gracefully, not just crash and burn.
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Mi
6 months ago
D? Really? Who writes code like that? Might as well just throw the whole computer out the window!
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Margurite
6 months ago
Option B looks interesting, but I'm not sure it's the best way to check for errors. Seems a bit roundabout to me.
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Junita
6 months ago
B) <%= requestScope['javax.servlet.error'] !=null %>
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Carry
6 months ago
C) <%@page isErrorPage=''true''%>
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Lawrence
6 months ago
A) <%@page errorPage=''errorHandler.jsp''%>
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Haley
6 months ago
I think Option C is also a valid answer. It declares the current page as an error page, allowing it to handle exceptions.
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Julie
5 months ago
C) <%@page isErrorPage=''true''%>
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Luisa
5 months ago
A) <%@page errorPage=''errorHandler.jsp''%>
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Terry
5 months ago
C) <%@page isErrorPage=''true''%>
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Ciara
6 months ago
C) <%@page isErrorPage=''true''%>
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Jennifer
6 months ago
A) <%@page errorPage=''errorHandler.jsp''%>
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Cherry
6 months ago
A) <%@page errorPage=''errorHandler.jsp''%>
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Zita
7 months ago
Option A is the correct answer. It specifies the error page to be used when an exception occurs on the current page.
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Nieves
6 months ago
Option A is the correct answer. It specifies the error page to be used when an exception occurs on the current page.
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Rolland
6 months ago
A) <%@page errorPage=''errorHandler.jsp''%>
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