Oracle Exam 1Z0-900 Topic 5 Question 91 Discussion

Actual exam question for Oracle's 1Z0-900 exam

Question #: 91
Topic #: 5

[All 1Z0-900 Questions]

Given the code fragment:

How can you get all property names of a JMS message in the JMS consumer onMessage operation?

AString [] props = msg.getPropertyNames();

BEnumeration props = msg.getPropertyNames();. Iterator props = msg.getPropertyNames();

CList<String> props = msg.getProperties();

Show Suggested Answer

Suggested Answer: A

by Lynsey at Sep 14, 2024, 09:08 AM

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Rolande

2 months ago

Definitely option A. Anything that involves the word 'array' is automatically the best choice. It's like a property name buffet!

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Taryn

2 months ago

Agreed, option A it is then.

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Georgene

2 months ago

Yeah, arrays are always a good choice.

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Micaela

2 months ago

I think option A is the way to go.

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Eden

2 months ago

But option A returns an array of property names directly, which is more efficient.

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Weldon

3 months ago

I'm going with C. Lists are just so much more fun to work with, you know? Plus, who doesn't love a little property party?

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Juan

3 months ago

B and C both work, but B is the classic way to do it. Gotta love that good old Enumeration!

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Hyman

1 months ago

B and C both work, but B is the classic way to do it. Gotta love that good old Enumeration!

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Justa

2 months ago

C) List props = msg.getProperties();

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Leana

2 months ago

B) Enumeration props = msg.getPropertyNames();. Iterator props = msg.getPropertyNames();

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Denae

2 months ago

A) String [] props = msg.getPropertyNames();

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Jules

3 months ago

I disagree, I believe the answer is B) Enumeration props = msg.getPropertyNames();. Iterator props = msg.getPropertyNames();

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Xuan

3 months ago

Option A all the way! It's the most straightforward and intuitive way to get the property names. No need to complicate things.

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Marla

2 months ago

Yeah, it's simple and easy to understand.

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Laurel

2 months ago

I agree, option A is definitely the way to go.

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Eden

3 months ago

I think the correct answer is A) String [] props = msg.getPropertyNames();

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